Calculate the height of a water-fall through which the fall of water leads to increase in its temperature by 10 C- Assume no energy is lost during process- Specific heat capacity of water -4200 J - kg - C Accelaration due to gravity -10 m - s 2A- 420 mB- 400 mC- 240 mD- 200 mE- 340 m

The correct option is A 420 mGiven Rise in temperature θ = 10C Specific heat capacity of water = 4200 J/kg ^∘ C Accelaration due to gravity = 10 m/s^2 Accord ...

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Standard IX

Physics

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Question

Calculate the height of a water-fall through which the fall of water leads to increase in its temperature by 1⁰C. Assume no energy is lost during process.

Specific heat capacity of water = $4200 J / k g^{\circ} C$

Accelaration due to gravity = $10 m / s^{2}$

420 m

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240 m

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400 m

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200 m

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340 m

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Solution

The correct option is A
420 m

Given

Rise in temperature $θ$ = 1⁰C

Specific heat capacity of water = $4200 J / k g^{\circ} C$

Accelaration due to gravity = $10 m / s^{2}$

According to law of conservation of energy potential energy of water is converted into to heat energy

$m g h$ = $m c_{t} θ$

$h$ = $\frac{4200}{10}$

$h$ = $420 m$

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Similar questions

Calculate the height of a water-fall through which the fall of water leads to increase in its temperature by 1⁰C.

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Calculate the height of a water-fall through which the fall of water leads to increase in its temperature by 10C. Assume no energy is lost during process. Specific heat capacity of water = 4200 J/kg ∘C Accelaration due to gravity = 10 m/s2

The correct option is A 420 mGiven Rise in temperature θ = 10C Specific heat capacity of water = 4200 J/kg ∘C Accelaration due to gravity = 10 m/s2 According to law of conservation of energy potential energy of water is converted into to heat energy mgh = mctθ h = 420010 h = 420 m

Calculate the height of a water-fall through which the fall of water leads to increase in its temperature by 1⁰C. Assume no energy is lost during process.

Specific heat capacity of water = $4200 J / k g^{\circ} C$

Accelaration due to gravity = $10 m / s^{2}$