Calculate the height through which a body of mass $0.5 k g$ is lifted if the energy spent in doing so is $1.0 J$ . (Take $g = 10 m s^{- 2}$ )

2 m

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0.2 m

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20 m

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0.4 m

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Solution

The correct option is B $0.2 m$
Energy spent equals the Work done against gravity while lifting.
Where, $W_{E x t} = Δ U_{G r a v i t a t i o n a l}$

Change in potential energy of the body in lifting the height h is given by:
$Δ U = m g h$

So, $1 J = 0.5 \times 10 m / s^{2} \times h$

$\Rightarrow h = 1 / 5 = 0.2 m$

Hence Option (B) is correct.

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