Question

Calculate the height to which liquid will rise in a capillary tube of radius ${10}^{-2}m$. Surface tension of liquid is $0.1N/m$. Angle of contact is ${60}^{\circ }$ & density of liquid is $2000{\text{kg/m}}^3$.

• A. $3\times {10}^{-4}m$
• B. $4\times {10}^{-4}m$
• C. $4.5\times {10}^{-4}m$
• D. $5\times {10}^{-4}m$

Answer 1

Answer: (D)

$5\times {10}^{-4}m$

Capillary Rise $h=\frac{2T\cos \theta }{r\rho g}$

$h=\frac{2\times 0.1\times \cos 60}{{10}^{-2}\times 2000\times 10}$
$h=\frac{2\times 0.1}{200}\times \frac{1}{2}$

$h=5\times {10}^{-4}m$