Calculate the hydrolysis constant of a salt of weak acid Ka - 2 -10-6 and weak base Kb - 5-10-7-

The correct option is B 10^ 2 We know that, hydrolysos constant, K_h= K_wK_a × K_b K_w = 10^ 14 , K_a = 2 ×10^ 6 #160;and K_b = 5×1 ...

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Standard XII

Chemistry

Factors Affecting Alpha

Calculate the...

Question

Calculate the hydrolysis constant of a salt of weak acid $(K_{a} = 2 \times 10^{- 6})$ and weak base $(K_{b} = 5 \times 10^{- 7})$ .

10^{- 4}

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10^{- 2}

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10^{- 6}

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10^{- 8}

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Solution

The correct option is B $10^{- 2}$
We know that, hydrolysos constant, $K_{h} = \frac{K_{w}}{K_{a} \times K_{b}}$
$K_{w} = 10^{- 14}$ , $K_{a} = 2 \times 10^{- 6}$ and $K_{b} = 5 \times 10^{- 7}$
$K_{h} = \frac{10^{- 14}}{2 \times 10^{- 6} \times 5 \times 10^{- 7}} = 10^{- 2}$

Hence, the correct option is B.

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Calculate the hydrolysis constant of a salt of weak acid (Ka=2×10−6) and weak base (Kb=5×10−7).

The correct option is B 10−2We know that, hydrolysos constant, Kh=KwKa×KbKw=10−14, Ka=2×10−6 and Kb=5×10−7Kh=10−142×10−6×5×10−7=10−2Hence, the correct option is B.

Calculate the hydrolysis constant of a salt of weak acid $(K_{a} = 2 \times 10^{- 6})$ and weak base $(K_{b} = 5 \times 10^{- 7})$ .