Calculate the increase in length of brass rod- which measures 100 cm at 10-C- when it is heated to 880-C - for brass - 0-000018-C

At $40^{\circ} C$ , a brass rod has a length 50 cm and a diameter 3.0 mm. It is joined to a steel rod of the same length and diameter at the same temperature. What is the change in the length of the composite rod when it is heated to $240^{\circ} C$ ? The coefficients of linear expansion of brass and steel are $2.0 \times 10^{- 5}^{\circ} C^{- 1}$ and $1.2 \times 10^{- 5}^{\circ} C^{- 1}$ respectively.

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Calculate the increase in length of brass rod, which measures 100 cm at 10∘C, when it is heated to 880∘C(∝ for brass =0.000018/∘C)

The correct option is D 15.66 cmL0=100 cm Increase in length =(Lt−Lo)α=0.000018/∘C =Loαtt=(880−10)∘C =100×0.000018×870=870∘C =15.66

Calculate the increase in length of brass rod, which measures $100 c m$ at $10^{\circ} C$ , when it is heated to $880^{\circ} C$
( $\propto$ for brass $= 0.000018 /^{\circ} C$ )

The correct option is D $15.66 c m$
$L_{0} = 100 c m$ Increase in length $= (L_{t} - L_{o})$
$α = 0.000018 /^{\circ} C$ $= L_{o} α t$
$t = (880 - 10)^{\circ} C$ $= 100 \times 0.000018 \times 870$
$= 870^{\circ} C$ $= 15.66$