Calculate the increase in mass when a body of rest mass 1 kg is lifted up through 1 m near the earth's surface.

21 \times 10^{- 16} k g

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1.11 \times 10^{- 16} k g

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1 \times 10^{- 16} k g

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51 \times 10^{- 16} k g

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Solution

The correct option is C $1.11 \times 10^{- 16} k g$ .
The increase in energy = mgh
$= (1 k g) (9.8 m s^{- 2}) (1 m) = 9.8 J$
The increase in mass $= \frac{9.8 J}{c^{2}}$
$= 1.11 \times 10^{- 16} k g$ .

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