Calculate the inductance of a solenoid containing 200 turns, a length of 25 cm and an area of cross section of 8cm2.
A
1.6×10−4H
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B
3.2×10−4H
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C
2.4×10−4H
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D
0.8×10−4H
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Solution
The correct option is A1.6×10−4H L=μ0n2V=4π×10−7×n2×v
n = no of turms in 1 metre
Given,
25 cm → 200 turms
so, 1m→ 800 turms
Therefore, n = 800 V=A×l=8×10−4×25×10−2=200×10−4×10−2=2×10−4