Calculate the inductance of a unit length of a double tape line as shown in figure. The tapes are separated by a distance h which is considerably less than their width b.
A
μ0hb
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B
μ0h2b
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C
2μ0hb
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D
√2μ0hb
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Solution
The correct option is Aμ0hb ∮→B⋅d→l=μ0I⇒B.2b=μ0I ⇒B=μ0I2b→ due to one tape Net field =2B Magnetic flux passing through this double tape ϕ=2BA=2B(lh)⇒ϕ=μ0Iblh L=ϕI=μ0lhb⇒Ll=μ0hb