Question

calculate the intensity of magnetization of Earth,assuming as a bar magnet of moment 8x10²² Am².radius of earth=6400 km

Answer 1

Dear Student,

Intensity of Magnetization : $I=\frac{M}{V}whereM=magneticmomentandV=volume$

$$\begin{gathered} VofEarth=\frac{4}{3}\times \pi \times {\left(6400\times {10}^3\right)}^3\Rightarrow 1.098\times {10}^{21}{m}^3 \\ I=\frac{8\times {10}^{22}}{1.098\times {10}^{21}}\Rightarrow 72.86A-m \end{gathered}$$

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