Calculate the intensity of the electric field due to a helium nucleus at a distance of $1 \circ A$ from the nucleus.

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Solution

Charge of helium nucleus $= + 2 e$
$= \frac{k (2 e)}{(1 A)^{2}}$
$= \frac{9 \times 10^{9} \times 2 \times 1.6 \times 10^{- 19}}{(10^{- 10})^{2}}$
$= 9 \times 2 \times 1.6 \times 10^{10}$
$= 2.88 \times 10^{11} N / C$ .

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Calculate the intensity of the electric field due to a helium nucleus at a distance of 1∘A from the nucleus.

Charge of helium nucleus =+2e=k(2e)(1A)2=9×109×2×1.6×10−19(10−10)2=9×2×1.6×1010=2.88×1011N/C.

Calculate the intensity of the electric field due to a helium nucleus at a distance of $1 \circ A$ from the nucleus.

Charge of helium nucleus $= + 2 e$
$= \frac{k (2 e)}{(1 A)^{2}}$
$= \frac{9 \times 10^{9} \times 2 \times 1.6 \times 10^{- 19}}{(10^{- 10})^{2}}$
$= 9 \times 2 \times 1.6 \times 10^{10}$
$= 2.88 \times 10^{11} N / C$ .