You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Zeff

Calculate the...

Question

Calculate the ionic radius of a Cs⁺ ion assuming the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl^- ion is 0.181 nm.

0.176 nm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.116 nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.358 nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.231 nm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
0.176 nm

Suggest Corrections

Similar questions

Q. Calculate the ionic radius of a

C s^{+}

ion assuming that the cell edge length for

C s C l

is 0.4123 nm and that the ionic radius of a

C l^{-}

ion is 0.181 nm.

C s C l

has cubic structure of ions in which

C s^{+}

ions is present in the body-centre of the cube. If density is

3.99 g c m^{- 3}

.
(a) Calculate the length of the edge of a unit cell.
(b) What is the distance between

C s^{+}

and

C l^{-}

ions?
(c) What is the radius of

C s^{+}

ion if the radius of

C l^{-}

ion is

180 p m

Q. If the length of body diagonal for

CsCl

, which crystallises into a cubic structure with

{Cl}^{-}

ions at the corners and

{Cs}^{+}

ions at the centre of unit cell is

7 ˚ A

and the radius of

{Cs}^{+}

ion is

1.69 ˚ A

. The radius of

{Cl}^{-}

ion?

Q. The unit cell cube length for

L i C l (N a C l

structure) is

514 \circ A

. Assuming anion-anion contact, calculate the ionic radius for chloride ion.

Q. The unit cell cube length for

L i C l

5.14 o A

. Assuming anion-cation contact, calculate the ionic radius for chloride ion.

Join BYJU'S Learning Program

Calculate the ionic radius of a Cs+ ion assuming the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl- ion is 0.181 nm.

The correct option is A 0.176 nm

Calculate the ionic radius of a Cs⁺ ion assuming the cell edge length for CsCl is 0.4123 nm and that the ionic radius of a Cl^- ion is 0.181 nm.

The correct option is A
0.176 nm