Calculate the kinetic energy and potential energy of the ball half way up, when a ball of mass 0.1 kg is thrown vertically upwards with an initial speed of $20 m s^{- 1}$ .

10 J, 20 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 J, 10 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

15 J, 8 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 J, 16 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 10 J, 10 J
Total energy at the time of projection
$= \frac{1}{2} m v^{2} = \frac{1}{2} \times 0.1 (20)^{2} = 20 J$
Half way up, P.E. becomes half the P.E. at the top i.e.
$P . E . = \frac{20}{2} = 10 J$ $∴ K . E . = 20 - 10 = 10 J$ .

Suggest Corrections

Similar questions

A ball of mass 0.20 kg is thrown vertically upwards with an initial velocity of 20 m s^-1 Calculate the maximum potential energy it gains as it goes up.

Q. An object of mass

40 k g

is raised to a height of

5 m

above the ground. What is its potential energy initially and at half way point? If the object is allowed to fall, find its kinetic energy when it is half-way down.

Calculate the kinetic energy of a body of mass 2 kg moving with a speed of $10 m s^{- 1} .$

Q. At a certain point the potential energy and kinetic energy of a body of mass 0.1 kg moving vertically up are 3.6 J and 6.2 J. It rises to a maximum height of :

A stone of mass 64.0 g is thrown vertically upward from the ground with an initial speed of 20.0 ms^-1. The gravitational potential energy at the ground level is considered to be zero. Applying the principle of conservation of energy, the potential energy attained the total energy of the stone at its halfway point can be calculated to be: (g= 10 m s^-2).

Join BYJU'S Learning Program

Calculate the kinetic energy and potential energy of the ball half way up, when a ball of mass 0.1 kg is thrown vertically upwards with an initial speed of 20ms−1.

The correct option is B 10 J, 10 JTotal energy at the time of projection =12mv2=12×0.1(20)2=20JHalf way up, P.E. becomes half the P.E. at the top i.e. P.E.=202=10J ∴K.E.=20−10=10J.

Calculate the kinetic energy and potential energy of the ball half way up, when a ball of mass 0.1 kg is thrown vertically upwards with an initial speed of $20 m s^{- 1}$ .

The correct option is B 10 J, 10 J
Total energy at the time of projection
$= \frac{1}{2} m v^{2} = \frac{1}{2} \times 0.1 (20)^{2} = 20 J$
Half way up, P.E. becomes half the P.E. at the top i.e.
$P . E . = \frac{20}{2} = 10 J$ $∴ K . E . = 20 - 10 = 10 J$ .