Calculate the kinetic Energy in Joules of 8 gm of Methane at 27- C - R -8-32A- 1-87 - 103B- 1-87 - 105C- 4-87 - 105D- 4-65 - 103

The correct option is A Number of moles in 8gm of CH_4=8/16=1/2 K.E. for 1 mole = 3/2RT=3/2× 8.32× 300 = 3744 Joules Thus, K.E. for 1/2 Mole of Methane = 3744/ ...

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Standard XII

Chemistry

Kinetic Theory of Gases

Calculate the...

Question

Calculate the kinetic Energy in Joules of 8gm of Methane at $27^{\circ}$ C. (R = 8.32)

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Solution

The correct option is A
Number of moles in 8gm of $C H_{4} = \frac{8}{16} = \frac{1}{2}$
K.E. for 1 mole = $\frac{3}{2} R T = \frac{3}{2} \times 8.32 \times 300$
= 3744 Joules
Thus, K.E. for $\frac{1}{2}$ Mole of Methane = $\frac{3744}{2}$
$= 1.87 \times 10^{3}$ Joules

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Calculate the kinetic Energy in Joules of 8gm of Methane at 27∘C. (R = 8.32)

The correct option is A Number of moles in 8gm of CH4=816=12 K.E. for 1 mole = 32RT=32×8.32×300 = 3744 Joules Thus, K.E. for 12 Mole of Methane = 37442 =1.87×103 Joules

Calculate the kinetic Energy in Joules of 8gm of Methane at $27^{\circ}$ C. (R = 8.32)

The correct option is A
Number of moles in 8gm of $C H_{4} = \frac{8}{16} = \frac{1}{2}$
K.E. for 1 mole = $\frac{3}{2} R T = \frac{3}{2} \times 8.32 \times 300$
= 3744 Joules
Thus, K.E. for $\frac{1}{2}$ Mole of Methane = $\frac{3744}{2}$
$= 1.87 \times 10^{3}$ Joules