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Work Energy Theorem

Calculate the...

Question

Calculate the kinetic energy of $5$ mole of a gas at $27^{\circ} C$ in erg and calorie.

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Solution

Kinetic Energy = $\frac{3}{2} n R T$
= $\frac{3}{2} \times 5 \times 8.314 \times 300 = 18765 J = 18765 \times 10^{7} e r g$
$1 c a l = 4.2 J$
Therefore, $18765 J = \frac{18765}{4.2} = 4467.85 c a l$

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