Calculate the length of $C^{'} A^{'}$ if $C A = 4$ $c m$ .

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Solution

$△$ ABC is enlarged to A'B'C' by 2.5
Hence. $\frac{C^{'} A^{'}}{C A} = 2.5$
$\frac{C^{'} A^{'}}{4} = 2.5$
$C^{'} A^{'} = 2.5 \times 4$
$C^{'} A^{'} = 10$ cm

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Similar questions

A triangle ABC has been enlarged by scale factor k = 2.5 to the triangle A' B' C'.

Calculate:

(i) the length of AB, if A' B' = 6cm.

(ii) the length of C'A' if CA= 4cm.

∣ ∣ ∣ ∣ \begin{matrix} b c & b c^{'} + b^{'} c & b^{'} c^{'} c a & c a^{'} + c^{'} a & c^{'} a^{'} a b & a b^{'} + a^{'} b & a^{'} b^{'} \end{matrix} ∣ ∣ ∣ ∣ = (a b^{'} - a^{'} b) (b c - b^{'} c) (c a^{'} - c^{'} a)

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\frac{C^{'} A^{'}}{C A}

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