Calculate the linear velocity of a point at equator on the earth surface due to its rotation (radius = 6400 km)
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Solution
Time period ,T=24hour=24*60*60=86400s Radius of earth,r=6400Km=6400000m linear velocity,v=ωr (ω-angukar velocity) =(2π/T)r =(2π/86400)*6400000 =465.185m/s (π=3.14)