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Question

Calculate the magnitude of velocity of the image (Vs) with respect to a stationary observer in the following situation ( Object moving at an angle with the mirror and mirror is stationary).

A
52m/s
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B
55m/s
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C
510m/s
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D
56m/s
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Solution

The correct option is A 52m/s
Let's resolve the velocity of the object as we discussed in the hint.

Velocity of object along the direction perpendicular to the mirror (horizontal direction),
−−−vo(hor)=5m/s (right)
Therefore, horizontal velocity of the image,
−−−vs(hor)=5m/s (left)

Now, the vertical velocity of the image is equal to that of the object, as required from object distance = image distance.
We have,
As, −−−vo(ver)=5m/s (down)
Therefore, −−−vs(ver)=5m/s (down)
Therefore, total velocity, Vs, has a magnitude of (5m/s)2+(5m/s)2=52ms.


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