Calculate the magnitude of velocity of the image (Vs) with respect to a stationary observer in the following situation ( Object moving at an angle with the mirror and mirror is stationary).
Now, the vertical velocity of the image is equal to that of the object, as required from object distance = image distance.
As, −−−−→vo(ver)=5m/s (down)
Therefore, −−−−→vs(ver)=5m/s (down)
Therefore, total velocity, →Vs, has a magnitude of √(5m/s)2+(5m/s)2=5√2ms.