Question

# Calculate the magnitude of velocity of the image (Vs) with respect to a stationary observer in the following situation ( Object moving at an angle with the mirror and mirror is stationary).

A
52m/s
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B
55m/s
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C
510m/s
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D
56m/s
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Solution

## The correct option is A 5√2m/sLet's resolve the velocity of the object as we discussed in the hint. Velocity of object along the direction perpendicular to the mirror (horizontal direction), −−−−→vo(hor)=5m/s (right) Therefore, horizontal velocity of the image, −−−−→vs(hor)=5m/s (left) Now, the vertical velocity of the image is equal to that of the object, as required from object distance = image distance. We have, As, −−−−→vo(ver)=5m/s (down) Therefore, −−−−→vs(ver)=5m/s (down) Therefore, total velocity, →Vs, has a magnitude of √(5m/s)2+(5m/s)2=5√2ms.

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