Calculate the mass and volume at NTP of hydrogen and chlorine that will be formed by passing $10, 000$ coulomb of charge through an aqueous solution of potassium chloride. The cell reaction is:
$2 K C l + 2 H O H \to 2 K O H + C l_{2} + H_{2}$ .

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Solution

$q = 10000$
$2 K C l + 2 H O H \to 2 K O H + C l_{2} + H_{2}$
$K C l \to C l_{2} + K O H$
$B y f e r a d a y f i r s t L a w$
$m = Z \times i \times t$
$m = Z Q$
$m = \frac{M o l . W t .}{n F} \times Q$
$m = \frac{70.9}{2 \times 96500} \times 10000$
$m a s s O f C l_{2} = 3.67 g$
$d e n s i t y O f C l_{2} A t S T P = 2.994 \frac{g r a m}{L}$
$V o l u m e O f C l_{2} = \frac{3.67}{2.994}$
$= 1.22578 L$
$f o r H_{2}$
$m = \frac{2}{2 \times 96500} \times 10000$
$m a s s O f H_{2} = 0.10362 g$
$d e n s i t y O f H_{2} = 0.083 \frac{g r a m}{L}$
$V o l u m e O f H_{2} = \frac{0.103}{0.083}$
$= 1.23 L$

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