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Question

Calculate the mass defect and binding energy in :

105B (isotopic mass = 10.01019 amu)

A
67.3 MeV
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B
99.9 MeV
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C
89.9 MeV
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D
None of the above
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Solution

The correct option is A 67.3 MeV
Binding energy is given as follows:
E=ΔE=Δm×931 MeV (as 1 amu =931 MeV)

Here,
Δm=(5mp+5mn)mass of B10

=(5×1.00759+5×1.008898)10.01019

=0.07225

ΔE=0.07225×931=67.26 MeV

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