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Standard X

Chemistry

Mole Concept

Calculate the...

Question

Calculate the mass in grams of available oxygen in $1$ litre of $H_{2} O_{2}$ solution if $10$ mL of this solution is allowed to react completely with $25$ mL of $\frac{N}{20} K M n O_{4}$ solution.

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Solution

The correct option is C $2$ g
Meq. of $H_{2} O_{2}$ in $10$ mL solution $=$ Meq. of $K M n O_{4} = 25 \times \frac{1}{20} = 1.25$
$∴$ Meq. of $H_{2} O_{2}$ in $1000$ mL $= \frac{1.25 \times 1000}{10} = 125$
$∴$ Meq. of $O_{2}$ formed $= 125$
$\frac{w}{\frac{32}{2}} \times 1000 = 125$ $[(O_{2})^{- 1} ⟶ (O_{2})^{0} + 2 e]$
$w_{O_{2}} = 2$ g
Hence, the mass of available oxygen in in $1$ litre of $H_{2} O_{2}$ solution is $2$ g.

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Similar questions

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Calculate the mass in grams of available oxygen in 1 litre of H2O2 solution if 10 mL of this solution is allowed to react completely with 25 mL of N20KMnO4 solution.

The correct option is C 2 gMeq. of H2O2 in 10 mL solution = Meq. of KMnO4=25×120=1.25∴ Meq. of H2O2 in 1000 mL =1.25×100010=125∴ Meq. of O2 formed =125w322×1000=125 [(O2)−1⟶(O2)0+2e]wO2=2 gHence, the mass of available oxygen in in 1 litre of H2O2 solution is 2 g.

Calculate the mass in grams of available oxygen in $1$ litre of $H_{2} O_{2}$ solution if $10$ mL of this solution is allowed to react completely with $25$ mL of $\frac{N}{20} K M n O_{4}$ solution.