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Stoichiometric Calculations

Calculate the...

Question

Calculate the mass (m) of oxalic acid $(H_{2} C_{2} O_{4})$ which can be oxidised to $C O_{2}$ by $100$ mL of an ${M n O_{4}}^{-}$ solution, $10$ mL of which is capable of oxidising $50.0$ mL of $1.00 N I^{-}$ to $I_{2}$ .
$M n O_{4} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$
$H_{2} C_{2} O_{4} \to 2 C O_{2} + 2 H^{+} + 2 e^{-}$
$2 I^{-} \to I_{2} + 2 e^{-}$
What is the value of $10 m$ ?

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Solution

$10$ mL of $N_{1} {M n O_{4}}^{-}$ corresponds to $50$ mL of $1.0 N I^{-}$ .
$10 \times N_{1} = 50 \times 1$
$N_{1} = 5 N$
The number of equivalents of $K M n O_{4}$ $= \frac{5 \times 100}{1000}$
The number of equivalents of oxalic acid is $0.5$ .
The mass of oxalic acid (m) that can be oxidized to carbon dioxide $= 0.5 \times 45$ g $= 22.5$ g
So, the value of $10 m$ is $225$ .

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