Calculate the mass of 0.1 mole of carbon dioxide.

[Atomic mass: S = 32, C = 12 and O=16 and Avogadro's Number = 6 x 10²³]

2.9 g

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3.7 g

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4.4 g

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5.2 g

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6.3 g

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Solution

The correct option is C
4.4 g

Mass of 1 mole of CO₂ is 44 g

Mass of 0.1 mole of CO₂ will be 44 x 0.1 = 4.4 g

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Similar questions

Calculate the mass of
(i) 10²² atoms of sulphur,
(ii) 0.1 mole of carbon dioxide.

[Atomic mass: S = 32, C = 12 and O = 16 and Avogadro's Number = 6 × 10²³]

Calculate the mass of 10²² atoms of sulphur.

[Atomic mass: S = 32, C = 12 and O=16 and Avogadro's Number = 6 x 10²³]

(a)

(i) Calculate the volume of 320 of $S O_{2}$ at STP. (Atomic mass : S = 32 and O = 16).
(ii) State Gay-Lussac's law of combining volume
(iii) Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane $(C_{3} H_{8})$ (Atomic mass; C = 12, 0 = 16, H = 1, Molar volume $- 22.4 d m^{3}$

(b)

(i) An organic compound with vapour density = 94 contains
C = 12.67% H = 2.13 % and Br = 85.11% Find the molecular formula.
[Atomic mass ; C = 12, H = 1, Br = 80]
(ii) Calculate the mass of
(1) $10^{22}$ Atoms of sulphur.
(2) 0.1 mole of carbon dioxide.
[Atomic mass; S = 32, C = 12 and O = 16 and Avogadro's number $= 6 \times 10^{23}$

Q. Calculate the number of moles of ethylene required to produce

44

g of carbon dioxide gas on its complete combustion.

[Atomic mass of

C = 12

u, Atomic mass of

H = 1

u, Atomic mass of

O = 16

u].

Calculate the number of molecules in 12.8 g of sulphur dioxide gas. Take Avogadro's number as 6 × 10²³.
[S = 32, O = 16]

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Calculate the mass of 0.1 mole of carbon dioxide. [Atomic mass: S = 32, C = 12 and O=16 and Avogadro's Number = 6 x 1023]

The correct option is C 4.4 gMass of 1 mole of CO2 is 44 g Mass of 0.1 mole of CO2 will be 44 x 0.1 = 4.4 g

Calculate the mass of 0.1 mole of carbon dioxide.

[Atomic mass: S = 32, C = 12 and O=16 and Avogadro's Number = 6 x 10²³]

The correct option is C
4.4 g

Mass of 1 mole of CO₂ is 44 g

Mass of 0.1 mole of CO₂ will be 44 x 0.1 = 4.4 g