Question

Calculate the mass of 3.011×10²³ number of nitrogen atoms.

Answer 1

Step 1:

We know that,
1 mole of atoms = 6.022 × ${10}^{23}$ atoms
So
6.022 x ${10}^{23}$ atoms = 1 mole
1 atoms = $\frac{1}{6.023\times {10}^{23}}$ mole
= 3.011 x ${10}^{23}$ atoms
= $\frac{3.011\times {10}^{23}}{6.023\times {10}^{23}}=\frac{1}{2}mole$
Step 2:
We also know that,
1 mole of atom = atomic weight
So.
1 mole of nitrogen = 14 grams
$\frac{1}{2}$ mole of nitrogen = $\frac{1}{2}\times 14$ = 7grams
So, mass of nitrogen atom = 7grams.