Question

Calculate the mass of $30.1\times {10}^{23}$ molecules of carbon dioxide gas:

• A. 88 g
• B. 132 g
• C. 176 g
• D. 220 g

Answer 1

The correct option is D 220 g

Mass of $6.02\times {10}^{23}$ molecules of $C{O}_2$ = molar mass of $C{O}_2$ = 44g
Thus mass of $30.1\times {10}^{23}$ molecules of $C{O}_2$ = $\frac{44\times 30.1\times {10}^{23}}{6.02\times {10}^{23}}$ = 220g