Calculate the mass of 50 cc of CO at s.t.p. [C=12,O=16]

Open in App

Solution

[1 mole = 1 gm mol. w.t & occupies 22.4 lit at s.t.p]
gm mol.wt. of carbon monoxide = 12+16=28 g
1 mole of CO = 1g mol. wt. Occupies 22400 cc[s.t.p]
28 g of CO occupies 224400 cc[s.t.p]
? g of CO will occupy 50 cc[s.t.p]
$\frac{28 \times 50}{22400} = 0.0625 g$
$\frac{1}{[M O L E]} = \frac{28 g [C O]}{[G . M O L W T]}$
$\frac{? g}{W E I G H T}$

Suggest Corrections

Similar questions

Q. The molecular formula of glucose is C₆H₁₂O₆. Calculate its molecular mass. (Atomic masses : C = 12 u ; H = 1 u ; O = 16 u)

(a) Calculate the mass of nitrogen supplied to the soil by 5 kg of urea $[C O (N H_{2})_{2}]$
$[O = 16 : N = 14; C = 12; H = 1]$
(b) Calculate the volume occupied by 320 g of sulphur dioxide at STP $[S = 32; O = 16]$

Calculate the formula unit masses of ZnO, Na₂O, K₂CO₃, given atomic masses of Zn = 65 u, Na = 23 u, K = 39 u, C = 12 u, and O = 16 u.

From the equation

C + 2 H_{2} {S O}_{4} \to {C O}_{2} + {2 H}_{2} O + 2 {S O}_{2}

. Calculate the mass of the carbon oxidized by 49g of sulphuric acid. (Atomic mass of C=12, H=1, S=32, O=16)

Q. Question 2
Calculate the formula unit masses of

Z n O, N a_{2} O, K_{2} C O_{3}

. Given atomic masses of Zn = 65 u, Na = 23 u, K = 39 u, C = 12 u, and O = 16 u.

Join BYJU'S Learning Program

Calculate the mass of 50 cc of CO at s.t.p. [C=12,O=16]

[1 mole = 1 gm mol. w.t & occupies 22.4 lit at s.t.p]gm mol.wt. of carbon monoxide = 12+16=28 g1 mole of CO = 1g mol. wt. Occupies 22400 cc[s.t.p]28 g of CO occupies 224400 cc[s.t.p]? g of CO will occupy 50 cc[s.t.p]28×5022400=0.0625g1[MOLE]=28g[CO][G.MOLWT]?gWEIGHT