Calculate the mass of air enclosed in a room of length, breadth and height equal to $5 m, 3 m$ and $4 m$ respectively. Density of air is $1.3 k g / m^{3}$ .

78 k g

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38 k g

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42 k g

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87 k g

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Solution

The correct option is A $78 k g$
The Volume of the room is given as $V = L \times B \times H = 5 \times 3 \times 4 = 60 m^{3} .$
We know, Mass $=$ Density $\times$ Volume.
Given that the density $= 1.3 k g / m^{3}$ .
So, Mass of the air $= 1.3 \times 60 K g$ .
Hence, mass of the air enclosed in the room is 78 kg.

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