Calculate the mass of $C O_{2}$ produced by heating $20 g$ of pure limestone $(C a C O_{3})$ .

20 g

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10 g

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8.8 g

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5.5 g

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Solution

The correct option is C 8.8 g
$C a C O_{3} \to C a O + C O_{2}$
Given mass of pure $C a C O_{3} = 20 g$
$100 g$ of $C a C O_{3}$ produce $44 g$ of $C O_{2}$
So, $20 g$ of $C a C O_{3}$ will produce $(\frac{44}{100} \times 20) = 8.8 g$ of $C O_{2}$

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