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Question

Calculate the mass of compound (molar mass = 256gmol1) to be dissolved in 75g of benzene to lower its freezing point by 0.48K(Kf=5.12Kkgmol1).

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Solution

Given data is

Tf=0.48 K, Kf=5.12kg mol1

M2=256 g mol1, W1=75 g, W2=?

We know that

ΔTf=Kf×w2×1000M2×w1

w2=ΔTf×M2×w1Kf×1000

0.48×256×755.12×1000

18 g

This the required solution.


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