Calculate the mass of Fe which will be converted into its oxide Fe3O4 by action of 18g of steam on it .

Open in App

Solution

The oxidation reaction of Fe is as follows:
2Fe + 3H₂O → Fe₂O₃ + 3H₂
i.e, 2 moles of Fe reacts with 3 moles of H₂O
Moreover,
18g of steam corresponds to 1 mole of H₂O which will react with 2/3 mole of Fe
Molecular mass of Fe₂O₃ = 55.847 g/mol
Hence,
Mass of Fe reacted = 55.847 x 2/3
= 37.23 g of Fe

Suggest Corrections

Similar questions

(F e_{3} O_{4})

8 g

F e = 56

F e + H_{2} O \to F e_{3} O_{4} + 4 H_{2}

3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

18 g

The mass of Fe converted to its oxide $F e_{3} O_{4}$ by the action of 18 g of steam is:

18 g

Join BYJU'S Learning Program