Calculate the mass of H2O and C2H5OH required to make 640 gm mixture having XH2O and XC2H5OH equal to 0.5
180 gm, 460 gm
It is given that
XH2O=XC2H5OH=0.5
But XH2O=Moles of H2OMoles of H2O + Moles of C2H5OH=0.5
⇒ Moles of H2O = Moles of C2H5OH
1 mole of H2O = 18 gm
1 mole of C2H5OH = 46 gm
This gives 64 gm
∴for 640 gm, we need 10 moles each ⇒ 180 gm H2O and 460 gm C2H5OH