Calculate the mass of hydrated copper sulphate required to produce 56-90 g of the complex compound assuming other reagents to be present in excess- CuSO 4 -5 H 2 O - CuSO 4-5 H 2 OCuSO 4-2 KCN - Cu CN 2- K 2 SO 42 Cu CN 2- 2 CuCN - CN 22 CuCN -6 KCN - 2 K 3- Cu CN 4-Molar mass of K -39 g - mol - Cu -63-5 g - mol A- 122-4 gB- 49-9 gC- 12-24 gD- 19-96 g

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Laws of Mass Conservation

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Question

Calculate the mass of hydrated copper sulphate required to produce 56.90 g of the complex compound assuming other reagents to be present in excess.
$C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O$
$C u S O_{4} + 2 K C N \to C u (C N)_{2} + K_{2} S O_{4}$
$2 C u (C N)_{2} \to 2 C u C N + (C N)_{2}$
$2 C u C N + 6 K C N \to 2 K_{3} [C u (C N)_{4}]$

$(Molar mass of K = 39 g / m o l, C u = 63.5 g / m o l)$

122.4 g

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19.96 g

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12.24 g

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49.9 g

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C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O

C u S O_{4} + 2 K C N \to C u (C N)_{2} + K_{2} S O_{4}

2 C u (C N)_{2} \to 2 C u C N + (C N)_{2}

2 C u C N + 6 K C N \to 2 K_{3} [C u (C N)_{4}]

(Molar mass of K = 39 g / m o l, C u = 63.5 g / m o l)

C u S O_{4} .5 H_{2} O

K C N

C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O (Yield = 100%)

C u S O_{4} + 2 K C N \to C u (C N)_{2} + K_{2} S O_{4} (Yield = 80%)

2 C u (C N)_{2} \to 2 C u C N + (C N)_{2} (Yield = 60%)

2 C u C N + 6 K C N \to 2 K_{3} [C u (C N)_{4}] (Yield = 50%)

C u S O_{4} .5 H_{2} O

2

(C u S O_{4} .5 H_{2} O)

C u = 63.5 g/mol

C u S O_{4} .5 H_{2} O

K C N

C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O (Yield = 100%)

C u S O_{4} + 2 K C N \to C u (C N)_{2} + K_{2} S O_{4} (Yield = 80%)

2 C u (C N)_{2} \to 2 C u C N + (C N)_{2} (Yield = 60%)

2 C u C N + 6 K C N \to 2 K_{3} [C u (C N)_{4}] (Yield = 50%)

C u S O_{4} .5 H_{2} O

[C u S O_{4} .5 H_{2} O]

C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O

C u = 64, S = 32, O = 16, H = 1

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