MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Calorimetry

Calculate the...

Question

Calculate the mass of ice needed to cool $150$ g of water contained in a calorimeter of mass $50$ g at $32^{o}$ C such that the final temperature is $5^{o}$ C.
Specific heat capacity of calorimeter $= 0.4 J / g^{o} C$
Specific heat capacity of water $= 4.2 J / g^{o} C$
Latent heat capacity of ice $= 330 J / g$ .

Open in App

Solution

Mass of water $m_{w} = 150 g$
Specific heat capacity of water $S_{w} = 4.2 J / g^{o} C$
Initial temperature $T_{i} = 32^{o} C$
Final temperature $T_{f} = 5^{o} C$
Mass of calorimeter $m_{c} = 50 g$
Specific heat capacity of calorimeter $S_{c} = 0.4 J / g^{o} C$
Heat released $Q = (m_{w} S_{w} + m_{s} S_{s}) (T_{i} - T_{f})$
$∴$ $Q = (150 \times 4.2 + 50 \times 0.4) (32 - 5) = 17550 J$
Mass of ice required $m_{i} = \frac{Q}{L}$
where $L = 330 J / g$
$∴$ $m_{i} = \frac{17550}{330} = 53.2 g$

Suggest Corrections

thumbs-up

4

Similar questions

Q. Find the result of mixing

10

- 10^{\circ}

10

10^{\circ}

C.Specific heat capacity of ice

= 2.1 J g^{- 1} K^{- 1}

, specific latent heat of ice

= 336 J g^{- 1}

and specific heat capacity of water

= 4.2 J g^{- 1} K^{- 1}

.

Q. A metallic calorimeter of mass 100g contains 200 g of ice and the initial temperature of the calorimeter and the ice is

- 10^{\circ} C

. Heat is supplied to the system containing calorimeter and ice at a constant rate of

50 c a l s^{- 1}

. Find the time required to raise the temperature of the system to

50^{\circ} C

. [Neglect the loss of heat to the surroundings].

Take specific heat capacity of calorimeter and ice as

0.2 c a l g^{- 1}^{\circ} C^{- 1}

\frac{1}{2} c a l g^{- 1}^{\circ} C^{- 1}

.Take latent heat of fusion of ice as

80 c a l g^{- 1}

and specific heat capacity of water as

1 c a l g^{- 1}^{\circ} C^{- 1}

Q. A calorimeter contains

400 g

of water at a temperature of

5^{\circ} C

200 g

of water at a temperature of

+ 10^{\circ} C

400 g

of ice at a temperature of

- 60^{\circ} C

are added. What is the final temperature(in

^{o} C

) of the contents of the calorimeter? Specific heat capacity of water

= 1000 c a l / k g / K

. Specific latent heat of fusion of ice

= 80 \times 1000 c a l / k g

. Relative specific heat of ice

= 0.5

Q. A calorimeter of mass

50 g

and specific heat capacity

0.42 J g^{- 1} ℃^{- 1}

contains some mass of water at

20^{o} C

. A metal piece of mass

20 g

100^{o} C

is dropped into the calorimeter. After stirring, the final temperature of the mixture is found to be

22^{o} C

. Find the mass of water used in the calorimeter.
[specific heat capacity of the metal piece

= 0.3 J g^{- 1} ℃^{- 1}

specific heat capacity of water

= 4.2 J g^{- 1} ℃^{- 1}

A vessel of negligible heat capacity contains 40 g of ice in it at 0⁰C. A metal of mass 50 g at 50⁰C is placed into the ice to melt it. The final temperature of the contents of the vessel is 10⁰C. Find the specific capacity of the metal.

(Specific latent heat of fusion of ice = 336 J/g and Specific heat capacity of water = 4.2 J/g⁰C)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Calorimetry

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon