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Standard XII

Physics

Latent Heat

Calculate the...

Question

Calculate the mass of ice required to lower the temperature of $300 g$ of water at $40 ° C$ to water at $0 ° C$ . (Specific latent heat of ice = 336 J /g, Specific heat capacity of water = 4.2 J/ g°C).

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Solution

Heat extracted by ice at $0^{o} C$ to melt = Heat given by water to reach $0^{o} C$ from $40^{o} C$ .
$M L = m c θ$
Where, $θ$ = change in temperature of water
L = Specific Latent heat of ice
c = Specific heat capacity of water
M = Mass of ice required
m = mass of water
$M \times 336 = 300 \times 4.2 \times (40 - 0)$
$M = \frac{300 \times 4.2 \times 40}{336} = 150 g$
$∴$ Ice required to lower the temperature of water $= 150 g$

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Similar questions

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, specific heat capacity of water =

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, specific latent heat of ice =

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Calculate the mass of ice required to lower the temperature of 300g of water at 40°C to water at 0°C. (Specific latent heat of ice = 336 J /g, Specific heat capacity of water = 4.2 J/ g°C).

Calculate the mass of ice required to lower the temperature of $300 g$ of water at $40 ° C$ to water at $0 ° C$ . (Specific latent heat of ice = 336 J /g, Specific heat capacity of water = 4.2 J/ g°C).