MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Stoichiometric Calculations

Calculate the...

Question

Calculate the mass of iron which will be converted into its oxide by the action of 18 g of steam.

Open in App

Solution

The reaction occurs as:
$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{3}$
$\frac{M o l e o f F e}{M o l e o f H_{2} O} = \frac{3}{4}$
Mole of $F e$ = $\frac{18}{18} \times \frac{3}{4}$
Weight of $F e$ = $\frac{3}{4} \times 56 = 42 g$

Suggest Corrections

thumbs-up

2

Similar questions

Q. The mass of iron (in g) which will be converted to its oxide by the action of

18

Q. Calculate the mass of iron which will be converted into its oxide

(F e_{3} O_{4})

by the action of

8 g

of steam on it. [At mass of

F e = 56

]

F e + H_{2} O \to F e_{3} O_{4} + 4 H_{2}

Q. Calculate the weight of Iron which will be converted into its oxide by the action of 18 g of steam.
Given the reaction :

3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}

(Atomic mass of Fe=56 g.

Q. Calculate the weight of iron which will be coverted into its oxide by the action of

18 g

of steam on it.

Q. Calculate the weight of iron which will be converted to its oxide by the action of

18 g

of steam on it when the yield of reaction is 50 %.

2 F e + 3 H_{2} O \to F e_{2} O_{3} + 3 H_{2}

56 g/mol

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Stoichiometric Calculations

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Stoichiometric Calculations

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon