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Byju's Answer
Standard XII
Chemistry
Valency and Oxidation State
Calculate the...
Question
Calculate the mass of
K
2
C
r
2
O
7
in grams required to produce
254
g
I
2
from
K
I
solution.
K
2
C
r
2
O
7
+
K
I
→
C
r
3
+
+
I
2
(Molar mass of
K
2
C
r
2
O
7
is
294
g
m
o
l
−
1
)
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Solution
K
2
+
6
C
r
2
O
7
+
K
−
1
I
→
+
3
C
r
3
+
+
0
I
2
n
f
=
(
|
Change in O.S.
|
)
×
Number of atoms
n
f
K
2
C
r
2
O
7
=
|
+
3
−
(
+
6
)
|
×
2
=
6
n
f
I
2
=
|
0
−
(
−
1
)
|
×
2
=
2
From the law of equivalence,
Equivalents of
K
2
C
r
2
O
7
=
Equivalents of
I
2
W
K
2
C
r
2
O
7
294
×
6
=
254
254
×
2
∴
W
K
2
C
r
2
O
7
≈
98
g
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0
Similar questions
Q.
Calculate the mass of
K
2
C
r
2
O
7
required to produce
254
g
I
2
from
K
I
solution.
K
2
C
r
2
O
7
+
K
I
→
C
r
3
+
+
I
2
(Molar mass of
K
2
C
r
2
O
7
is
294
g
m
o
l
−
1
)
Q.
Calculate the mass of
K
2
C
r
2
O
7
required to produce
254
g
I
2
from
K
I
solution.
K
2
C
r
2
O
7
+
K
I
→
C
r
3
+
+
I
2
(Molar mass of
K
2
C
r
2
O
7
is
294
g
m
o
l
−
1
)
Q.
An excess
K
I
solution is mixed in a solution of
K
2
C
r
2
O
7
and liberated iodine required
72
m
L
of
0.05
N
N
a
2
S
2
O
3
for complete reaction. How many grams of
K
2
C
r
2
O
7
were present in the solution of
K
2
C
r
2
O
7
? The reaction occurs as:
C
r
2
O
7
2
−
+
6
I
−
+
14
H
+
→
2
C
r
3
+
+
3
I
2
+
7
H
2
O
Q.
0.5
g mixture of
K
2
C
r
2
O
7
and
K
M
n
O
4
was treated with excess of
K
I
in acidic medium. Iodine liberated required
150
c
m
3
of
0.10
N
solution of thiosulphate solution for titration. Find the percentage of
K
2
C
r
2
O
7
in the mixture.
Q.
0.5
g mixture of
K
2
C
r
2
O
7
and
K
M
n
O
4
is treated with excess of
K
I
in acidic medium.
I
2
liberated requires
100
mL of
0.15
N
N
a
2
S
2
O
3
solution for titration.
%
of
K
2
C
r
2
O
7
and
%
of
K
M
n
O
4
are:
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