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Valency and Oxidation State

Calculate the...

Question

Calculate the mass of $K_{2} C r_{2} O_{7}$ in grams required to produce $254 g I_{2}$ from $K I$ solution.
$K_{2} C r_{2} O_{7} + K I \to C r^{3 +} + I_{2}$

(Molar mass of $K_{2} C r_{2} O_{7}$ is $294 g m o l^{- 1}$ )

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Solution

$K_{2} + 6 C r_{2} O_{7} + K - 1 I \to + 3 C r^{3 +} + {0 I}_{2}$

$n_{f} = (| Change in O.S. |) \times Number of atoms$
$n_{f_{K_{2} C r_{2} O_{7}}} = | + 3 - (+ 6) | \times 2 = 6$
$n_{f_{I_{2}}} = | 0 - (- 1) | \times 2 = 2$

From the law of equivalence,
$Equivalents of K_{2} C r_{2} O_{7} = Equivalents of I_{2}$
$\frac{W_{K_{2} C r_{2} O_{7}}}{294} \times 6 = \frac{254}{254} \times 2$
$∴ W_{K_{2} C r_{2} O_{7}} \approx 98 g$

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