Calculate the mass of Nacl required to prepare 0.25 mol solution in 500 ml of water.

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Solution

$M o l a r i t y = \frac{N o o f m o l e s}{V o l o f t h e s o l u t i o n i n L} = \frac{M a s s o f t h e g i v e n s u b s \tan c e i n g / M o l a r m a s s}{V o l o f t h e s o l u t i o n i n L} 0.25 = \frac{M a s s o f t h e g i v e n s u b s t a n c e i n g / 58.5}{0.500} M a s s o f t h e g i v e n s u b s t a n c e i n g = 0.25 \times 58.5 \times 0.500 = 7.3125 g$

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