Question

Calculate the mass of sodium acetate $\left(C{H}_{3}COONa\right)$ required to make $500mL$ of $0.375$ molar aqueous solution. Molar mass of sodium acetate is $82.0245gmo{l}^{–1}.$

Answer 1

Calculate of mass of sodium acetate:

Description

Given volume of sodium acetate solution $=500mL$

Molarity of solution $=0.375M$

Molar mass of sodium acetate$=82.0245gmo{l}^{-1}$

We know, molarity$=\frac{\text{moleofsolute(mol)}}{\text{Volumeofsolution(L)}}$

and molarity$=\frac{\text{massof(CH\_3 COONa)}\times \text{1000}}{\text{molarmassofCH\_3 COONa}\times \text{Volumeofsolution(mL)}}$

So, mass of $C{H}_{3}COONa=\frac{0.375mol{L}^{-1}\times 82.0245gmo{l}^{-1}\times 500mL}{1000}$

$\{1L=1000mL\}$

Mass of $C{H}_{3}COONa=15.379\simeq 15.38g$

Final answer: mass of sodium acetate $\left(C{H}_{3}COONa\right)$ required is $15.38g$