Calculate the mass of sodium acetate $(C H_{3} C O O N a)$ require to make 500 mL of 0.375 M solution:

10.45 g

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12.36 g

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15.88 g

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15.38 g

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Solution

The correct option is A 15.38 g
0.375 M solution of $C H_{3} C O O N a$ = 0.375 moles of $C H_{3} C O O N a / 1000 m l$
No. of moles of $C H_{3} C O O N a$ in 500ml = $\frac{0.375}{1000} \times 500 = 0.1875 m o l e s$
Molar mass of sodium acetate = 82.0245 g/mole
$∴$ mass of $C H_{3} C O O N a$ required $= 82.0245 \times 0.1875 = 15.38 g$

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