Question

Calculate the mass of sodium acetate $\left[C{H}_{3}COONa\right]$ required to make $500$ mL of $0.375$ molar aqueous solution. Molar mass of sodium acetate is $82.0245$ g $mo{l}^{-1}$.

Answer 1

$0.375M$ solution means $0.375$ moles in $1L$ of solution.

$1000mL$ of solution contains $0.375$ moles

$1mL$ of solution$⟶\frac{0.375}{1000}$moles

$500mL$ of solution$⟶\frac{0.375}{1000}\times 500$

$⟶0.1875$

$No.ofmoles=\frac{Mass}{MolarMass}$

$0.1875mol=\frac{Mass}{82.0245{gmol}^{-1}}$

$\therefore$ Mass of the compound = $15.37g$.