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Non-Ideal Solutions

calculate the...

Question

calculate the mass of the compound whose molar mass is 256 gram per mole to be dissolved in 75 gram of benzene to elevate its boiling point by 0.48 Kelvin where KB for benzene is 3.28 Kelvin kg per mole

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Solution

Dear Student

ΔT_b = imolality of solution K_b
K_b=3.28 K kg mol^-1
ΔT_b=0.48K
Assuming the value of i to be 1 (since nothing is specified)
the molality of solution = ΔT_b/ K_b= 0.48 / 3.28 = 0.146 mol kg^-1
molality = mass of solute/(molar mass of solute * mass of solvent (in kg))
0.146 = mass of solute / (256* 7510^-3)
Hence mass of solute = 0.146256* 0.075 gram = 2.8 grams

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