Calculate the mass per cent composition of copper in copper sulfate.(Cu=64,S=32,O=16)

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Solution

The atomic weight of copper is 64 amu.
The molecular weight of the Copper Sulfate $[{CuSO}_{4}]$ will be $(1 \times 64) + (1 \times 32) + (4 \times 16) = 160 amu$
The mass per cent composition of an element in a compound is given by $\frac{Atomic weight of element}{Molecular weight of compound} \times 100$
The mass per cent composition of copper in a copper sulfate is given by $\frac{64}{160} \times 100 = 40 %$
The mass per cent composition of copper ( $Cu$ ) in copper sulfate $[{CuSO}_{4}]$ is 40%.

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Copper on reacting with concentrated H₂SO₄ produces copper sulphate. If 1.28g of copper is to be converted to copper sulphate, find:

(a) The weight of copper sulphate formed.

(b) Weight of sulphuric acid required.

[Cu=64, S=32, O=16]

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