Calculate the mass per cent of different elements present in sodium sulphate $(N a_{2} S O_{4})$ .

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Solution

Molar mass of $N a_{2} S O_{4}$ = $23 \times 2 + 32 + 4 \times 16 = 142$

$N a = \frac{23 \times 2}{142} \times 100 = 32.4 %$

$S = \frac{32}{142} \times 100 = 22.5 %$

$O = \frac{64}{142} \times 100 = 45 %$

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