Question

Calculate the mass percentage composition of the elements in nitric acid (H = 1, N = 14, O = 16).

Answer 1

Nitric acid $HN{O}_3$ - mol wt. $=1+14+48$

$=63$ $g$

Mass percentage of hydrogen $=\frac{1}{63}\times 100=1.586$

Mass percentage of nitrogen $=\frac{14}{63}\times 100=22.22$

Mass percentage of oxygen $=\frac{48}{63}\times 100=76.19$

Hence the percentage of $H$,$N$and $O$ are $1.58$ and $76.19$ respectively.