Calculate the mass percentage of benzene $(C_{6} H_{6})$ and carbon tetrachloride $(C C l_{4})$ if $22 g$ of benzene is dissolved in $122 g$ of carbon tetrachloride.

Open in App

Solution

In general Mass % of $X = [\frac{Mass of X}{Mass of total mixture}] \times 100$

Mass of the total mixture= $22 + 122 = 144 g$
Mass % of benzene= $(\frac{22}{144}) \times 100 = 15.28$ %
Mass % of $C C l_{4} = (\frac{122}{144}) \times 100 = 84.72$ %

Suggest Corrections

Similar questions

22 g

122 g

30 %

calculate the mole fracton of benzene ina solution containing 30% by mass of it in carbon tetrachloride

Join BYJU'S Learning Program