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Question

Calculate the max.work done by system in an irreversible (single step) adiabatic expansion of 1 mole of a polyatomic gas from 300K and pressure 10atm to 1 atm. (γ=1.33)

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Solution

Initial temperature (T1)=300K
Final temperature (T2)=T(say)=?
Initial pressure (P1)=10atm
Final pressure (P2)=1atm
γ=43
For an adiabatic process,
TγPγ1=constant
(T1T2)γ=(P1P2)γ1
(300T)=(101)11γ
300T=(10)14
T=3001.77=168.72K=T2
ΔT=(168.72300)=131.28K
Therefore, for an adiabatic expansion,
W=ΔU=nCVΔT
W=1×Rγ1×(131.28)
W=3R×(131.28)=393.84R
Hence the maximum amount of work done by the system will be 393.84R.

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