Question

Calculate the maximum spin and the spin magnetic moment (in B.M.) for the atom having 6 unpaired electrons.

• A. 3 ,$\sqrt{15}$
• B. 3, $\sqrt{48}$
• C. 2, $\sqrt{8}$
• D. 4, $\sqrt{80}$

Answer 1

The correct option is B 3, $\sqrt{48}$

Given,
Number of unpaired electrons = 6
Therefore, maximum spin for the atom = $\frac{1}{2}\times$ (number of unpaired electrons)
=$\frac{1}{2}\times 6=3$

Also spin magnetic moment =$\sqrt{n(n+2)}B.M.$
=$\sqrt{6(6+2)}BM=\sqrt{48}B.M.$