Question

Calculate the maximum work done for isothermal reversible expansion of 1 mole of a polyatomic gas at ${50}^{o}C$ and 10 atm to 1 atm; [$\gamma =1.33$].

• A. -2415J
• B. -6184.5J
• C. -1244J
• D. -2142J

Answer 1

Answer: (B)

-6184.5J

The work required is given by the expression :

$w=-2.303nRT\times log\frac{P_1}{P_2}$.

Substitute values in the above expression.

$w=-2.303\times 1\times 8.314\times 323\times log\frac{10}{1}=-6184.5J$