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Question

Calculate the mean deviation about mean for the following data.

ClassFrequency01041020112030153040204050950605

A
10.92
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B
11.65
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C
13.7
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D
12.15
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Solution

The correct option is A 10.92
ClassXFFX010542010201511165203025153753040352070040504594055060555275F=64FX=1940

Mean, ¯x=FXF=194064=30.3

Deviations from the mean are tabulated below

X (class midpoint)FD=|X¯x|FD5425.3101.2151115.3168.325155.379.535204.79445914.7132.355524.7123.5 F=64FD=698.8

M.D(¯x)=698.864=10.92

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